'이형'에 속하는 라틴어 단어 (1685)

conpartior

(동사), [[compartior|compartior]]

conpatior

(동사), [[compatior|compatior]]

conpectum

(명사), [[compectum|compectum]]

conpediō

(동사), [[compedio|compediō]]

conpellātiō

(명사), [[compellatio|compellātiō]]

conpellō

(동사), [[compello|compellō]]

conpendium

(명사), [[compendium|compendium]]

conperiō

(동사), [[comperio|comperiō]]

conpēs

(명사), [[compes|compēs]]

conpēscō

(동사), [[compesco|compēscō]]

conpetītor

(명사), [[competitor|competītor]]

conpetō

(동사), [[competo|competō]]

conpetum

(명사), [[compitum|compitum]]

conpīlō

(동사), [[compilo|compīlō]]

conpingō

(동사), [[compingo|compingō]]

conpitum

(명사), [[compitum|compitum]]

conplaceō

(동사), [[complaceo|complaceō]]

conplānō

(동사), [[complano|complānō]]

conplantō

(동사), [[complanto|complantō]]

conplector

(동사), [[complector|complector]]

conpleō

(동사), [[compleo|compleō]]

conplētiō

(명사), [[completio|complētiō]]

conplexiō

(명사), [[complexio|complexiō]]

conplexō

(동사), [[complexo|complexō]]

conplexus

(명사), [[complexus]]

conplicō

(동사), [[complico|complicō]]

conplōdō

(동사), [[complodo|complōdō]]

conpluor

(동사), [[compluor|compluor]]

conplūrēs

(형용사), [[complures|complūrēs]]

conpōnō

(동사), [[compono|compōnō]]